1 /*
2  * Copyright 2010 Tilera Corporation. All Rights Reserved.
3  *
4  *   This program is free software; you can redistribute it and/or
5  *   modify it under the terms of the GNU General Public License
6  *   as published by the Free Software Foundation, version 2.
7  *
8  *   This program is distributed in the hope that it will be useful, but
9  *   WITHOUT ANY WARRANTY; without even the implied warranty of
10  *   MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE, GOOD TITLE or
11  *   NON INFRINGEMENT.  See the GNU General Public License for
12  *   more details.
13  */
14 
15 #include <linux/types.h>
16 #include <linux/string.h>
17 #include <linux/module.h>
18 
19 #undef strchr
20 
strchr(const char * s,int c)21 char *strchr(const char *s, int c)
22 {
23 	int z, g;
24 
25 	/* Get an aligned pointer. */
26 	const uintptr_t s_int = (uintptr_t) s;
27 	const uint32_t *p = (const uint32_t *)(s_int & -4);
28 
29 	/* Create four copies of the byte for which we are looking. */
30 	const uint32_t goal = 0x01010101 * (uint8_t) c;
31 
32 	/* Read the first aligned word, but force bytes before the string to
33 	 * match neither zero nor goal (we make sure the high bit of each
34 	 * byte is 1, and the low 7 bits are all the opposite of the goal
35 	 * byte).
36 	 *
37 	 * Note that this shift count expression works because we know shift
38 	 * counts are taken mod 32.
39 	 */
40 	const uint32_t before_mask = (1 << (s_int << 3)) - 1;
41 	uint32_t v = (*p | before_mask) ^ (goal & __insn_shrib(before_mask, 1));
42 
43 	uint32_t zero_matches, goal_matches;
44 	while (1) {
45 		/* Look for a terminating '\0'. */
46 		zero_matches = __insn_seqb(v, 0);
47 
48 		/* Look for the goal byte. */
49 		goal_matches = __insn_seqb(v, goal);
50 
51 		if (__builtin_expect(zero_matches | goal_matches, 0))
52 			break;
53 
54 		v = *++p;
55 	}
56 
57 	z = __insn_ctz(zero_matches);
58 	g = __insn_ctz(goal_matches);
59 
60 	/* If we found c before '\0' we got a match. Note that if c == '\0'
61 	 * then g == z, and we correctly return the address of the '\0'
62 	 * rather than NULL.
63 	 */
64 	return (g <= z) ? ((char *)p) + (g >> 3) : NULL;
65 }
66 EXPORT_SYMBOL(strchr);
67