Searched refs:c_i (Results 1 – 4 of 4) sorted by relevance
| /linux/Documentation/translations/zh_CN/scheduler/ |
| H A D | sched-bwc.rst | 124 该接口强制要求单个实体的带宽总是可以达到的，即：max(c_i) <= C。然而，在总体情况下，是明确
127 例如，Sum (c_i)可能超过C
129 [ 其中C是父方的带宽，c_i是其子方的带宽。 ]
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| /linux/drivers/iio/ |
| H A D | inkern.c | 326 struct iio_map_internal *c_i = NULL, *c = NULL; in iio_channel_get_sys() local
334 list_for_each_entry(c_i, &iio_map_list, l) { in iio_channel_get_sys()
335 if ((name && strcmp(name, c_i->map->consumer_dev_name) != 0) || in iio_channel_get_sys()
337 strcmp(channel_name, c_i->map->consumer_channel) != 0)) in iio_channel_get_sys()
339 c = c_i; in iio_channel_get_sys()
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| /linux/Documentation/scheduler/ |
| H A D | sched-bwc.rst | 144 attainable, that is: max(c_i) <= C. However, over-subscription in the
148 e.g. \Sum (c_i) may exceed C
150 [ Where C is the parent's bandwidth, and c_i its children ]
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| /linux/Documentation/translations/sp_SP/scheduler/ |
| H A D | sched-bwc.rst | 172 sea siempre factible, esto es: max(c_i) <= C. De todas maneras,
177 e.g. \Sum (c_i) puede superar C
179 [ Donde C es el ancho de banda de el padre, y c_i el de su hijo ]
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