Searched refs:no_of_ctrls (Results 1 – 2 of 2) sorted by relevance
29 .no_of_ctrls = 1,39 .no_of_ctrls = 2,50 .no_of_ctrls = 2,61 .no_of_ctrls = 2,89 if (rsrc->no_of_ctrls == 2) in acp_irq_handler() 102 if (chip->rsrc->no_of_ctrls == 2) { in acp_irq_handler()
38 (0x4 + (chip->rsrc->no_of_ctrls * 0x04)), ctrl)