Lines Matching full:cpu1
61 - work_per_hz(CPU1) = W/2
67 - capacity(CPU1) = C/2
69 To draw the parallel with Arm big.LITTLE, CPU0 would be a big while CPU1 would
80 CPU1 work ^
86 work W in T units of time. On the other hand, CPU1 has half the capacity of
96 - max_freq(CPU1) = 2/3 * F
101 - capacity(CPU1) = C/3
111 workload on CPU1
112 CPU1 work ^
190 - capacity(CPU1) = C/3
200 CPU1 work ^
208 - duty_cycle(p) == 75% if p runs on CPU1 at its maximum frequency
379 capacity(CPU1) = C / 3
388 workload on CPU1