Lines Matching full:foo

48  foo.bar.baz = value1
49  foo.bar.qux.quux = value2
53  foo.bar {
60  foo.bar { baz = value1; qux.quux = value2 }
71  foo = bar, baz
72  foo = qux  # !ERROR! we can not re-define same key
77  foo = bar, baz
78  foo := qux
80 then, the ``qux`` is assigned to ``foo`` key. This is useful for
87  foo = bar, baz
88  foo += qux
90 In this case, the key ``foo`` has ``bar``, ``baz`` and ``qux``.
95  foo = value1
96  foo.bar = value2 # !ERROR! subkey "bar" and value "value1" can NOT co-exist
97  foo.bar := value2 # !ERROR! even with the override operator, this is NOT allowed.
109  foo = value # value is set to foo.
116  foo = value